Q.

The rate of a first order reaction is 0.04M.S1 at 10 min and 0.03M.S1 at 20 min after initiation rate constant value is y×104 min1. Find  value of y0.875?        (log104=0.6020,  log103=0.477)

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answer is 287.

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Detailed Solution

r1r2=C1C2  (n=1storderrc)

γ1γ2=C1C2  =0.040.03K=2.303t20t10logC1C2

K=2.30310log4×1023×102K=287×104min1

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