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Q.

The rate of a gaseous reaction is given by the expression k (A) (B). if the volume of the reaction vessel is suddenly reduced to ¼ of the initial vol. the reaction rate relative to the original rate will be

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a

$\frac{1}{16}$

b

$\frac{1}{8}$

c

8

d

16

answer is D.

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Detailed Solution

If volume is reduced to 1/4^th concentration will be increased 4 times hence reaction rate

will increase by 16. Rate = k[A][B].

New rate = k [4A] [4B] = 16k[A][B]

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The rate of a gaseous reaction is given by the expression k (A) (B). if the volume of the reaction vessel is suddenly reduced to ¼ of the initial vol. the reaction rate relative to the original rate will be