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The rate of a gaseous reaction is given by the expression $k {[A]}^{2} {[B]}^{3}$ . The volume of the reaction vessel is reduced to one half of the initial volume. What will be the reaction rate as compared to the original rate ‘a’ ?

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$\frac{1}{8} a$

$\frac{1}{2} a$

32a

answer is D.

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Detailed Solution

Rate = $k {[A]}^{2} {[B]}^{3}$
Rate $\propto C^{5}$

$\begin{array}{l} R a t e \propto {(\frac{n}{V})}^{5} \\ R a t e \propto {(\frac{1}{\frac{1}{2}})}^{5} = 32 a \end{array}$

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