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The rate of a reaction between A and B follows the rate law :
$Rate = k {[A]}^{2} [B]$
Determine the rate of Experiment Two in the table below at the same temperature as Experiment One.
Exp. [A], M [B], M Observed rate, mol $L^{- 1} s^{- 1}$
1 0.10 0.10 R
2 0.30 0.20 ?

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3 R

6 R

12 R

18 R

answer is D.

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Detailed Solution

$Rate = k {[A]}^{2} [B]$

For condition 2

$A_{2} = 3 A, B_{2} = 2 A$

$R_{2} = K {[3 A]}^{2} [2 A] R_{2} = K \times 9 {[A]}^{2} \times 2 [B] R_{2} = 18 K {[A]}^{2} [B] R_{2} = 18 R$

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