Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be:
R=8.314JK1mol1 and log2=0.301

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

48.6 kJ mol1

b

58.5 kJ mol1

c

60.5 kJ mol1

d

53.6 kJ mol1

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

As per Arrhenius equation:

Question Image

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be:R=8.314JK−1mol−1 and log⁡2=0.301