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The rate of a reaction gets doubled when the temperature changes from 7° C to 17° C. By what factor will it change for the temperature change from 17° C to 27° C?

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1.81

1.71

1.91

1.76

answer is C.

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Detailed Solution

$\begin{array}{l} \ln 2 = Δ H \times \frac{10}{280 \times 290} \\ \ln (μ) = Δ H \times \frac{10}{290 \times 300} \\ \Rightarrow \frac{\ln (μ)}{\ln 2} = \frac{280}{300} \\ = \ln 1.91 \end{array}$

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