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The rate of a reaction is expressed in different ways as follows:
$+ 1 / 2 (d [C] / dt) = - 1 / 3 (d [D] / dt) = + 1 / 4 (d [A] / dt) = - (d [B] / dt)$ The reaction is:

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$4 A + B \to 2 C + 3 D$

$B + 3 D \to 4 A + 2 C$

$4 A + 2 B \to 2 C + 3 D$

$B + (1 / 2) D \to 4 A + 3$

answer is B.

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Detailed Solution

$\begin{array}{l} - \frac{1}{3} \frac{d [D]}{dt} = - \frac{d [B]}{dt} = \frac{1}{2} \frac{d [C]}{dt} = \frac{1}{4} \frac{d [A]}{dt} \\ B + 3 D \to 4 A + 2 C \end{array}$

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