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Q.

The rate of diffusion of gas A is double that of the gas B. The ratio of their molecular weights is

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a

1:4

b

1:2

c

4:1

d

2:1

answer is B.

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Detailed Solution

As per given statement,

$r_{A} = 2 r_{B}$

$\frac{r_{A}}{r_{B}} = \sqrt{\frac{M_{B}}{M_{A}}}$

$\Rightarrow \frac{2 r_{B}}{r_{B}} = \sqrt{\frac{M_{B}}{M_{A}}}$

$\Rightarrow \frac{2}{1} = \sqrt{\frac{M_{B}}{M_{A}}}$

$\Rightarrow \frac{M_{B}}{M_{A}} = \frac{4}{1}$

so, $M_{A} : M_{B} = 1 : 4$

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The rate of diffusion of gas A is double that of the gas B. The ratio of their molecular weights is