The rate of formation of SO3 in the following reaction: 2SO2+O2→2SO3 is 10 g sec-1. The rate of disappearance of O2 will be

2SO2+O2→2SO3rSO3=10 g/sec=1080 mol/secAlso, rO21=rSO32⇒rO2=1080×12 mol/sec=(10160)×32 g/sec=2 g/sec

The rate of formation of SO3 in the following reaction: 2SO2+O2→2SO3 is 10 g sec-1. The rate of disappearance of O2 will be

2SO2+O2→2SO3rSO3=10 g/sec=1080 mol/secAlso, rO21=rSO32⇒rO2=1080×12 mol/sec=(10160)×32 g/sec=2 g/sec

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The rate of formation of ${SO}_{3}$ in the following reaction:
$2 {SO}_{2} + O_{2} \to 2 {SO}_{3}$ is 10 g $s e c^{- 1}$ . The rate of disappearance of $O_{2}$ will be

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$5 {g sec}^{- 1}$

$100 {g sec}^{- 1}$

$20 g sec$

$2 {g sec}^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} 2 {SO}_{2} + O_{2} \to 2 {SO}_{3} \\ r_{{SO}_{3}} = 10 g/sec= \frac{10}{80} mol/sec \\ Also, \frac{r_{O_{2}}}{1} = \frac{r_{{SO}_{3}}}{2} \Rightarrow r_{O_{2}} = \frac{10}{80} \times \frac{1}{2} mol/sec \\ = (\frac{10}{160}) \times 32 g/sec=2 g/sec \end{array}$