The rate of reaction starting with initial concentration of 2×10−3 M and 10−3M are equal to 2.4×10−4mol dm−3sec−1 and 0.6×10−4mol dm−3 sec−1 respectively. Find rate constant of reaction in units mol−1dm3n−3sec−1 where n = order of reaction.

Here, we have,log⁡(2.40×104/0.60×104)log⁡2×103/1×103=log⁡4log⁡2=2Order is 2 for this case. Rate constant,2.4×104molL1s12×103molL12=60×103mol−1L−1s1

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The rate of reaction starting with initial concentration of $2 \times 10^{- 3}$ M and $10^{- 3} M$ are equal to $2.4 \times 10^{- 4} mol {dm}^{- 3} \sec^{- 1}$ and $0.6 \times 10^{- 4} mol {dm}^{- 3} \sec^{- 1}$ respectively. Find rate constant of reaction in units $[{mol}^{- 1} {dm}^{3 n - 3} \sec^{- 1}]$ where n = order of reaction.

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Detailed Solution

Here, we have,

$\frac{\log (2.40 \times 104 / 0.60 \times 104)}{\log (2 \times 103 / 1 \times 10^{3})} = \frac{\log 4}{\log 2} = 2$

Order is 2 for this case. Rate constant,

$\frac{2.4 \times 104 {molL}^{1} s^{1}}{{(2 \times 10^{3} {molL}^{1})}^{2}} = 60 \times 10^{3} {mol}^{- 1} L^{- 1} s^{1}$

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