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Q.

The ratio between the neutrons present in carbon atom and silicon atoms with mass numbers 12 and 28 is  : 

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a

7:3

b

1:2

c

3:7

d

2:1

answer is B.

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Detailed Solution

6C12  - number of neutrons in C=12−6=6

14Si28  - number of neutrons in Si=28−14=14

Carbon : Silicon

6:14

3:7

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