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The ratio between the neutrons present in carbon atom and silicon atoms with mass numbers 12 and 28 is

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3 : 7

2 : 1

1 : 2

7 : 3

answer is B.

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Detailed Solution

Consider only the stable isotopes of Carbon( ₆C¹² ) and silicon ( ₁₄Si²⁸ )

Number od neutrons in ₆C¹² = 6

Number of neutrons in ₁₄Si²⁸ = 14

Ratio of neutrons in ₆C¹² and ₁₄Si²⁸ is 6:14
i.e., 3:7.

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