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Q.

The ratio between the neutrons present in carbon atom and silicon atoms with mass numbers 12 and 28 is

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a

3 : 7

b

2 : 1

c

1 : 2

d

7 : 3

answer is B.

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Detailed Solution

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Consider only the stable isotopes of Carbon( 6C12 ) and silicon ( 14Si28 )

Number od neutrons in 6C12 = 6

Number of neutrons in 14Si28 = 14

Ratio of neutrons in 6C12 and 14Si28 is 6:14
                                                   i.e., 3:7.

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