The ratio between the number of molecules in equal masses of nitrogen and oxygen is

Use the following formula to find the ratio of molecules.

$\frac{\mathrm{no}.\mathrm{of} \mathrm{molecules} {\mathrm{N}}_2}{\mathrm{no} \mathrm{of} \mathrm{molecules} {\mathrm{O}}_2}=\frac{\left(1/28\right)\times N_A}{\left(1/32\right)\times N_A}=\frac{32}{28}=\frac{8}{7}$

The ratio between no. of molecules in equal masses of ${\mathrm{N}}_2:{\mathrm{O}}_2 \mathrm{is} 8:7$