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Q.

The ratio in which the line segment joining the points whose position vectors are 2i^4j^7k^ and 3i^+5j^8k^ is divided by the plane whose equation is   r^(i^2j^+3k^)=13 is

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a

13 : 12 internally

b

12: 25 externally

c

13 : 25 internally

d

37: 25 internally

answer is B.

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Detailed Solution

Let P be the point and it divides the line segment in the ratio λ:1 Then, 
OP=r=3λ+2λ+1i^+5λ4λ+1j^+8λ7λ+1k^

It satisfies r(i^2j^+3k^)=13. So, 

3λ+2λ+125λ4λ+1+38λ7λ+1=13or  3λ+22(5λ4)+3(8λ7)=13(λ+1)or  37λ11=13λ+13 or 50λ=24 or λ=1225

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