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Q.

The ratio of angular momentum of an electron in two orbits of the hydrogen atom is 1 : 3. The ratio of the energies of the electron in these orbits is

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a

3 : 1

b

9 : 1

c

81 : 1

d

27 : 1

answer is C.

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Detailed Solution

We know angular momentum 

mvr=nh2π

it is proportional to n (orbit No)

energy is proportional to 1/n2

so energy ratio is 9:1

 

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