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The ratio of charge densities on the surface of two conducting spheres is 3 : 2. If the radii of the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere is

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3 : 1

4 : 9

3 : 4

1 : 3

answer is A.

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Detailed Solution

$V = \frac{σr}{ε_{0}}; \frac{V_{1}}{V_{2}} = \frac{σ_{1} r_{1}}{σ_{2} r_{2}} = \frac{3}{2} \times \frac{4}{8} = \frac{3}{4}$

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