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Q.

The ratio of charge densities on the surface of two conducting spheres is 3 : 2. If the radii of the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere is

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a

3 : 1

b

4 : 9

c

3 : 4

d

1 : 3

answer is A.

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Detailed Solution

V=σrε0;V1V2=σ1r1σ2r2=32×48=34

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