The ratio of earth’s orbital angular momentum to its mass is 4.4x1015m2 /s. The area enclosed by earth’s orbit is X (1022) m2, then X = _____.

Lm=4.4X1015m2/sdAdt=L2mdA=L2mdtdA=12×4.4×1015×365×24×3600dA=6.94×1022 m2

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The ratio of earth’s orbital angular momentum to its mass is 4.4x10¹⁵m² /s. The area enclosed by earth’s orbit is X (10²²) m², then X = _____.

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answer is 6.94.

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Detailed Solution

$\frac{L}{m} = 4 .4 X 10^{15} m^{2} / s$

$\frac{dA}{dt} = \frac{L}{2 m}$

$dA = \frac{L}{2 m} dt$

$dA = \frac{1}{2} \times 4 .4 \times 10^{15} \times 365 \times 24 \times 3600$

$d A = 6 .94 \times 10^{22} m^{2}$

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