The ratio of electric fields due to an electric dipole at equal distances in its axial and equatorial position will be

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1 : 1

1 : 2

2 : 1

1 : 4

answer is C.

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Detailed Solution

For a dipole $E = \frac{1}{4 {πε}_{0} r^{3}} \times p \sqrt{(1 + 3 \cos^{2} θ)}$
$∴ E_{a} = \frac{2 p}{4 {πε}_{0} r^{3}} (∵ θ = 0)$
and $E_{e} = \frac{p}{4 {πε}_{0} r^{3}} (∵ θ = 90)$
$∴ \frac{E_{a}}{E_{e}} = 2 : 1$

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