The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance 5 x 10^-11m, will be (charge on electron = 1.6 x 10^-19 C, mass of electron = 9.1 x 10^-31 kg, mass of proton = 16 x 10^-27 kg, G = 6.7 X 10^-11 N-m² /kg²)

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

2.36 x 10³⁹

2.36 x 10⁴⁰

2.34 X 10⁴¹

2.34 x 10⁴²

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Gravitational force,

$F_{G} = \frac{G m_{e} m_{p}}{r^{2}}$

$F_{G} = \frac{6.7 \times 10^{- 11} \times 9.1 \times 10^{- 31} \times 1.6 \times 10^{- 27}}{{(5 \times 10^{- 11})}^{2}}$

$= 3.9 \times 10^{- 47} N$

Electrostatic force, $F_{e} = \frac{1}{4 π ε_{0}} \frac{e^{2}}{r^{2}}$

$F_{e} = \frac{9 \times 10^{9} \times 1.6 \times 10^{- 19} \times 1.6 \times 10^{- 19}}{{(5 \times 10^{- 11})}^{2}}$

$= 9.22 \times 10^{- 8} N$

$So, \frac{F_{e}}{F_{G}} = 2.3 \times 10^{39}$

Watch 3-min video & get full concept clarity