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The ratio of intensities at two points P and Q on the screen in a Young’s double slit experiment where phase difference between two waves of same amplitude are $π / 3$ and $π / 2$ , respectively are

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3:1

3:2

2:3

1:3

answer is B.

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Detailed Solution

Intensity at any point on screen in YDSE
$I = I_{max} \cos^{2} (ϕ / 2) where ϕ = phase difference between waves \frac{I_{p}}{I_{Q}} = \frac{\cos^{2} (π / 6)}{\cos^{2} (π / 4)} = \frac{3 / 4}{1 / 2} = \frac{3}{2}$

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