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Q.

The ratio of ionization energy of Bohr’s hydrogen atom and Bohr’s hydrogen like lithium atom is(Assume both atoms in ground state)

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a

1 : 1

b

1 : 3

c

1 : 9

d

None of these

answer is C.

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Detailed Solution

$I.E = (13.6 z^{2}) eV$

$\Rightarrow \frac{{IE}_{1}}{{IE}_{2}} = \frac{1^{2}}{3^{2}} = \frac{1}{9}$

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