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The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is

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1 : 4

7 : 32

1 : 8

3 : 16

answer is B.

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Detailed Solution

$\frac{n_{O_{2}}}{n_{N_{2}}} = \frac{\frac{(m_{O_{2}})}{(M_{O_{2}})}}{\frac{(m_{N_{2}})}{(M_{N_{2}})}}$
$= (\frac{m_{O_{2}}}{m_{N_{2}}}) \frac{28}{32} = \frac{1}{4} \times \frac{28}{32}$
$= \frac{7}{32}$

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