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Q.

The ratio of maximum to minimum possible radiation energy in Bohr’s hypothetical hydrogen atom is equal to

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a

2

b

3/2

c

4/3

d

4

answer is C.

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Detailed Solution

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$\begin{array}{l} E = Rch Z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) \\ ∴ {(E_{1})}_{max} = Rch (1) (\frac{1}{1^{2}} - \frac{1}{\infty^{2}}) \to (1) \\ ∴ {(E_{2})}_{min} = Rch (1)^{2} (\frac{1}{1^{2}} - \frac{1}{2^{2}}) \to (2) \\ \frac{E_{max}}{E_{min}} = \frac{1}{3 / 4} = \frac{4}{3} \end{array}$

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The ratio of maximum to minimum possible radiation energy in Bohr’s hypothetical hydrogen atom is equal to