The ratio of percentage s-character of C-atom in $\mathrm{ethyne}$ and ethene is equal to

$\begin{array}{l}\text{The \% of }\mathrm{s}\text{-character of C-atom in ethyne is 50\%}\\ \text{The \% of }\mathrm{s}\text{-character of C-atom in ethene is 33\%}\\ \mathrm{ratio}=\frac{50}{33}=\frac{3}{2}=3 : 2\end{array}$