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The ratio of resolving powers of an optical microscope for two wave lengths $λ_{1}$ = 4000 $\overset{0}{A}$
and $λ_{2} = 6000 \overset{0}{A}$ is

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16:81

8:27

9:4

3:2

answer is D.

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Detailed Solution

$\ Resolving\,\,power\,\,(R) = \frac{a}{{1.22\,\lambda }}\$

$\frac{{{R_1}}}{{{R_2}}} = \frac{{{\lambda _2}}}{{{\lambda _1}}} = \frac{{6000}}{{4000}} = \frac{3}{2}\$

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