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The ratio of sum of first three terms of a G.P.to the sum of first six terms is 64 : 91, the common ratio of G.P. is

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answer is B.

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Detailed Solution

Given $\frac{s_{3}}{s_{6}} = \frac{64}{91} = \frac{a (r^{3} - 1)}{a (r^{6} - 1)} \Rightarrow \frac{(r^{3} - 1)}{(r^{3} + 1) (r^{3} - 1)} = \frac{64}{91} \Rightarrow r^{3} = \frac{27}{64} ∴ r = \frac{3}{4}$

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