The ratio of the e/m (specific charge) values of an electron and an alpha-particle is :

The ratio of the e/m (specific charge) values of an electron and an a-particle is none of these.

For electron:

$\frac{e}{m}=\frac{1.6\times {10}^{-19}\mathrm{c}}{9.1\times {10}^{-31}\mathrm{kg}}$

For $\mathrm{\alpha }-$particle

$\left({\mathrm{He}}^{+2}\right)\frac{e}{m}=\frac{2\times 1.6\times {10}^{-19}\mathrm{c}}{4\times 1.6\times {10}^{-27}\mathrm{kg}}$

$\frac{(e\mid m)e}{(e\mid m)\alpha }=\left(\frac{1.6\times {10}^{-19}}{9.1\times {10}^{-31}}\right)\times \left(\frac{4\times 1.6\times {10}^{-27}}{2\times 1.6\times {10}^{-19}}\right)$

$\frac{(e\mid m)e}{(e\mid m)\alpha }=3516$

Hence, the option D is correct.