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The ratio of the energies of two different radiations whose frequencies are $3 \times 10^{14} Hz & 5 \times 10^{14} Hz is$

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3 : 1

5 : 3

3 : 5

5 : 1

answer is A.

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Detailed Solution

𝐸 = ℎ $ϑ$

$\frac{E_{1}}{E_{2}} = \frac{ϑ_{1}}{ϑ_{2}} = \frac{3 \times 10^{14}}{5 \times 10^{14}}$

$\frac{E_{1}}{E_{2}} = 3 : 5$ .

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