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Q.

The ratio of the intensities at minima to maxima in the interference pattern is 9 : 25. What will be the ratio of the widths of the two slits in the young's double slit experiment?

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a

8 : 1

b

9 : 1

c

16 : 1

d

4 : 1

answer is C.

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Detailed Solution

$\frac{I_{max}}{I_{min}} = {[\frac{\sqrt{\frac{I_{1}}{I_{2}}} + 1}{\sqrt{\frac{I_{1}}{I_{2}}} - 1}]}^{2}$ = $\frac{{(a_{1} + a_{2})}^{2}}{{(a_{1} - a_{2})}^{2}} \Rightarrow \frac{a_{1} + a_{2}}{a_{1} - a_{2}} = \frac{5}{3} \Rightarrow \frac{a_{1}}{a_{2}} = \frac{4}{1}$

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