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Q.

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5^th excited state of a hydrogen atom is :

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a

$1$

b

$\frac{1}{2}$

c

$4$

d

$\frac{1}{4}$

answer is C.

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Detailed Solution

$\frac{1}{2} | PE | = KE$ for each value of n (orbit)

$∴ \frac{KE}{| PE |} = \frac{1}{2}$

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