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Q.

The ratio of the number of hybrid and pure orbitals in C6H6 used for bonding is

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a

3 : 2

b

2 : 3

c

4 : 3

d

1 : 1

answer is C.

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Detailed Solution

  •  Each carbon in benzene undergoes sp2 hybridization. 
  • Carbon has 2s and 2p orbitals participate in the hybridization that creates 3sp2 hybrid orbitals, while its 1s and one 2p orbital do not. Since H only has one 1s orbital and that orbital cannot be hybridised, H remains in its pure form. As a result, a benzene ring has 18 hybridised orbitals (3 from each carbon) as well as 18 pure orbitals (2 from each carbon and 1 from each hydrogen). Therefore, the ratio of hybridised to pure orbitals is 1:1. 
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