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Q.

The ratio of the number of neutrons present in one atom each of C and Si with respect to mass number of 12 and 28 respectively is :

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a

3 : 7

b

7 : 3

c

3 : 4

d

3 : 14

answer is A.

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Detailed Solution

Number of neutrons in Carbon = 12 - 6 = 6
Number of neutrons in Silicon = 28 - 14
= C : Si = 6 : 14 = 3 : 7

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