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The ratio of the number of $s p, s p^{2} & s p^{3}$ hybrid orbitals in the compound $C H_{3} - C H = C = C H - C \equiv C - C H_{3}$ is___

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$2 : 2 : 1$

$3 : 2 : 1$

$1 : 1 : 1$

$3 : 3 : 4$

answer is D.

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Detailed Solution

No of $s p^{3}$ hybrid orbitals=8
No of $s p^{2}$ hybrid orbitals=6
No. of sp hybrid orbitals=6

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