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The ratio of the radii of gyration of a circular disc about a tangential axis in the plane of the disc and of a circular ring of the same radius about a tangential axis in the plane of the ring is

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2 : 3

2 : 1

$\sqrt{5} : \sqrt{6}$

$1 : \sqrt{2}$

answer is D.

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Detailed Solution

$I_{d} = \frac{m r^{2}}{4} + m r^{2} = m k_{1}^{2}$

$I_{d} = \frac{m r^{2}}{2} + m r^{2} = m k_{2}^{2}$

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