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The ratio of the radii of the three Bohr orbits is

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1:1:1

1:2:3

1:4:9

1:8:27

answer is C.

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Detailed Solution

$r = \frac{n^{2} a_{0}}{z}, (when n = 1, Z = 1)$

$\begin{array}{l} r_{1} = a_{0} \\ r_{2} = 4 a_{0} (when n = 2, Z = 1) \\ r_{3} = 9 a_{0} (when n = 3, Z = 1) \end{array}$

Hence , ratio is 1:4:9.

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