Q.

The ratio of the radii of two Bohr's orbit of H-atom: is 4 : 1. What would be their nomenclature ?

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a

K and L

b

both (b) and (c) 

c

L and K

d

N and L

answer is D.

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Detailed Solution

we now that

Radii of Bohr's orbit =0.529×(n)22

For H- atom z=1

r=0.529×(n)2

For K- shell  n=1,  r=0.529×(1)2=0.529.

 L- shell  n=2 ,  r=0.529×(2)2 =0.529×4

 M- shell  n=3, r=0.529×(3)2=0.529×9

N- shell  n=4,  r=0.529×(4)2=0.529×16

LK=0.529×40.529=41

NL=0.529×160.529×4=41

 

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