The ratio of vapour pressure of two liquids A and B in pure state is 1 : 2. If the two liquids are mixed and the ratio of their mole fraction in vapour phase is 2 : 1 of A and B respectively, then the ratio in which liquids A and B were mixed is ____

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answer is 4.

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Detailed Solution

$\begin{array}{l} P_{A} = P_{A}^{0} X_{A (ℓ)} = P_{T} \cdot X_{A (g)} \\ P_{B} = P_{B}^{0} x_{B (ℓ)} = P_{T} x_{B (g)} \\ \frac{P_{A}^{0}}{P_{B}^{0}} {(\frac{x_{A}}{x_{B}})}_{ℓ} = {(\frac{x_{A}}{x_{B}})}_{g} \\ {(\frac{x_{A}}{x_{B}})}_{ℓ} = \frac{2}{1} \times \frac{2}{1} = 4 \end{array}$

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