The reactant which is entirely consumed in the reacton is known as limiting reagent. In the reaction $2A+4B\to 3C+4D,$ when 5 moles of A react with 6 moles of B, then which is the limiting reagent and what would be the amount of C formed respectively?

$$\begin{gathered} 2A+4B\to 3C+4D \\ 5 6 \end{gathered}$$

Limiting reactant is declared which have lowest

ratio of $\frac{Moles}{coefficient}$for reactant.

$\text{ For A: }\frac{5}{2}=2.5$

$\text{ For }\mathrm{B}:\frac{6}{4}=1.5\Rightarrow \mathrm{B}$ is limiting reagent.

$$\begin{gathered} 2A+4B\to 3C+4D \\ 5 6 \end{gathered}$$

Here, 5 mole of A need 10 mole of B to react, thus B is a limiting agent.
3 moles of A can react with 6 moles of B, thus the number of moles of C formed

$=\frac{3}{2}\times 3=4.5\mathrm{mol}$