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Q.

The reaction A(g) + 2B(g) $\to$ C(g) + D(g) is an elementary process. In an experiment involving this reaction, the initial partial pressure of A and B are p_A= 0.60 atm and p_B = 0.80 atm, respectively. When p_C= 0.20 atm, the rate of reaction relative to the initial rate is

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a

1/6

b

1/12

c

1/36

d

1/18

answer is A.

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Detailed Solution

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$\begin{aligned} A (g) + 2 B (g) ⟶ C (g) + D (g) \\ t = 0 0.6 0.8 - - \\ t = t 0.4 0.4 0.2 0.2 \\ r_{0} = k \times 0.6 \times (08)^{2} \\ r_{t} = k \times 0.4 \times (0.4)^{2} \\ \Rightarrow \frac{r_{t}}{r_{0}} = \frac{0.4 \times (0.4)^{2}}{0.6 \times (0.8)^{2}} = \frac{1}{6} \end{aligned}$

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