The reaction between gaseous NH₃ and HBr produces a white solid NH₄Br. Suppose that NH₃ and HBr are introduced simultaneously into the opposite ends of an open tube of 1 metre long. Wherewould you expect the white solid to form.

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At a distance of 68.5 cm from NH₃ end

At a distance of 44.45 cm from HBr end

At a distance of 45.45 cm from HBr end

At a distance of 34.45 cm from NH₃ end

answer is B.

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Detailed Solution

Let both the gases meet at distance = x cm from NH₃ end.

Distance from HBr end = ( 100 - x ) cm

Distance travelled is represented as d cm.

$\large \frac{d_{NH_{3}}}{d_{HBr}}\;=\sqrt{\frac{M_{HBr}}{M_{NH_{3}}}}$

$\large \frac{x}{100-x}\;=\sqrt{\frac{81}{17}}$

$\large x\;=68.5\;cm$

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