The reaction between X and Y is first order with respect to X and zero order with respect to Y
$E x p e r i m e n t \frac{[X]}{m o l L^{- 1}} \frac{[Y]}{m o l L^{- 1}} \frac{I n i t i a l r a t e}{m o l L^{- 1} \min^{- 1}}$
            I.                                 0.1                   0.1                   $2 \times 10^{- 3}$
            II.                                 L                      0.2                      $4 \times 10^{- 3}$
            III.                                0.4                  0.4                     $M \times 10^{- 3}$
            IV.                                0.1                   0.2                     $2 \times 10^{- 3}$
            Examine the data of table and calculate ratio of numerical values of M and L. (Nearest Integer)

Question

Accepted Answer

r=k[x][y]0=k[x]Using I and IIRate IVRate III=k[L]1k[0.1]1=4×10−32×10−3=(L0.1)=L=0.2Using III and IVM×10−32×10−3=k[0.4]k[0.1]⇒M=8ML=80.2=40

Detailed Solution