The reaction conditions leading to the best yield of $C_{2} H_{5} Cl$ are

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$C_{2} H_{6} (excess) + {Cl}_{2} \overset{uvlight}{⟶}$

$C_{2} H_{6} + {Cl}_{2} \underset{room temperature}{\overset{dark}{⟶}}$

$C_{2} H_{6} + {Cl}_{2} (excess) \to$

$C_{2} H_{6} + {Cl}_{2} \overset{uv light}{⟶}$

answer is A.

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Detailed Solution

When chlorinating an alkane, the likelihood of mono-chlorination is higher if an excess of the alkane is treated with ${Cl}_{2}$ (g) in the presence of light or heat.

$C_{2} H_{6} (excess) + {Cl}_{2} \overset{UV-light}{⟶} {CH}_{3} {CH}_{2} Cl + HCl$

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