The reaction involved during the removal of temporary hardness of water is

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$large Ca{(HC{O_3})_{2;}}xrightarrow{{;;;Delta ;;;}}CaC{O_3}; + ;{H_2}O; + ;C{O_2} uparrow$

CaCl₂ + Na₂CO₃ → CaCO₃ ↓ + 2NaCl

MgSO₄ + Na₂Al₂Si₂O₈xH₂O → Mg Al₂Si₂O₈ xH₂O + Na₂SO₄

2CaCl₂ + (NaPO₃)₆ → Na₂[Ca₂(PO₃)₆] + 4NaCl

answer is A.

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Detailed Solution

The temporary hardness of water is due to the presence of bicarbonates of Ca & Mg .
i.e,. Mg[HCo₃]₂
Ca[HCo₂]₃
Temporary hardness of water is removed by boiling, during this process the soluble bicarbonates converting into insoluble carbonates.

large Ca{left( {HC{o_3}} right)_2};xrightarrow{Delta };CaC{o_3} downarrow ; + {H_2}O; + ;C{O_2}

The insoluble precipiate is removesd by filterration.
Options 3,4 are equations related to removal of permanent hardness of water.

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