The reaction of with ${CH}_{3} OH$ in (i) acid $H^{+}$ , and (ii) base ${CH}_{3} O^{-},$ respectively, give

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${({CH}_{3})}_{2} C (OH) {CH}_{2} OH$ and ${({CH}_{3})}_{2} C ({OCH}_{3}) {CH}_{2} {OCH}_{3}$

${({CH}_{3})}_{2} C ({OCH}_{3}) {CH}_{2} OH$ and ${({CH}_{3})}_{2} CH (OH) {CH}_{2} {OCH}_{3}$

${({CH}_{3})}_{2} C ({OCH}_{3}) {CH}_{2} OH$ and ${({CH}_{3})}_{2} C ({OCH}_{3}) {CH}_{2} OH$

${({CH}_{3})}_{2} C ({OCH}_{3}) {CH}_{2} {OCH}_{3}$ and ${({CH}_{3})}_{2} C (OH) {CH}_{2} OH$

answer is A.

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Detailed Solution

There occurs cleavage of ether linkage in oxiranes (cyclic three-membered ring including oxygen). In acid-catalyzed reaction, nucleophile $^{-} {OCH}_{3}$ from ${CH}_{3} OH$ attaches to the more substituted carbon whereas in base-catalyzed reaction, it is attached to the less substituted carbon.