The reaction of an element A with water produces combustible gas B and an aqueous solution of C. When another substance D reacts with this solution C also produces the same gas B. D also produces the same gas even on reaction with dilute H₂S0₄ at room temperature. Element A imparts golden yellow colour to Bunsen flame. Then, A, B, C and D may be identified as :

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K, H₂ , NaOH and Zn

Ca, H₂ , Ca(OH)₂ and Zn

Na, H₂ , NaOH and Zn

K, H₂ , KOH and Zn

answer is A.

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Detailed Solution

$2 Na + 2 H_{2} O \to 2 NaOH + H_{2}$ (gas)
Na, H₂, and NaOH would make up an aqueous solution of C, a flammable gas, and element A, respectively.
This solution's solution C also generates the same gas as B when D reacts with it.
${Na}_{2} [Zn (OH)_{4}] + H_{2}$ = $Zn + 2 NaOH + 2 H_{2} O$
So, Na, H₂, NaOH, and Zn can be used to represent A, B, C, and D, respectively.