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The reaction of aqueous $K M n O_{4}$ with $H_{2} O_{2}$ in acidic conditions gives

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${Mn}^{2 +} and O_{3}$

${Mn}^{2 +} and O_{2}$

${Mn}^{4 +} and O_{2}$

${Mn}^{4 +} and Mn O_{2}$

answer is B.

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Detailed Solution

$Hydrogen peroxide is oxidised to H_{2} O and O_{2}$

$2 {KMnO}_{4} + 3 H_{2} {SO}_{4} + 5 H_{2} O_{2} ⟶ K_{2} {SO}_{4} + 2 {MnSO}_{4}$ $+ 8 H_{2} O + 5 O_{2}$

$or, 2 {MnO}_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} ⟶ 2 {Mn}^{2 +} + 8 H_{2} O + 5 O_{2}$

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