The reaction of ROH with R'MgX produces

The reaction of ROH with R'MgX produces R'H

$\mathrm{ROH}+{\mathrm{R}}^{\mathrm{\prime }}\mathrm{MgX}⟶\mathrm{ROMgX}+{\mathrm{R}}^{\mathrm{\prime }}\mathrm{H}$

The fundamental structure of an alcohol molecule is an alkyl group containing an oxygen atom, a hydrogen atom, and R. This structure is represented by the symbol ROH. Alcohols are compounds having this feature, similar to water, H₂O, but with an alkyl group in place of one hydrogen atom.