The reaction of white phosphorus with aqueous (hot and conc.) NaOH gives phosphine along with another phosphorus containing compound.
The reaction type, oxidation state of phosphorus in phosphine and other product respectively are :

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redox reaction ; -3 and -5

redox reaction; +3 and +5

disproportionation reaction ; -3 and+1

disproportionation reaction ; -3 and +3

answer is C.

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Detailed Solution

$\overset{0}{P_{4}} + 3 NaOH + 3 H_{2} O \to \overset{- 3}{{PH}_{3}} + 3 Na H_{2} \overset{+ 1}{{PO}_{2}}$

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