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Q.

The reaction A+B⟶AB has an enthalpy of reaction of −85.0 kJ−mol−1. If the activation. enthalpy for the forward reaction is 120.0 kJ mol−1 what is the activation energy for the reverse reaction AB⟶A+B?

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a

85.0 kJ⋅mol−1

b

205.0 kJ⋅mol−1

c

120.0 kJ⋅mol−1

d

35.0 kJ⋅mol−1

answer is D.

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Detailed Solution

The activation energy for the reverse reaction is the difference of both enthalpy.

Ea=120-(-85) Ea=205 kJ-mol-1

 

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