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Q.

The reaction A(g)+2B(g)C(g)+D(g)is an elementary process. In an experiment involving this reaction, the initial partial pressures of A and B are pA=0.60and pB=0.80atm respectively. When pC=0.20atm, the rate of the reaction relative to the initial rate is 

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a

1 /12

b

1 /36

c

1 /18

d

1 /6

answer is A.

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Detailed Solution

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A(g)+2B(g)C(g)+D(g)  Rate =k[A][B]2=k(0.60)(0.80)2....(i)  when pc=0.20 atm pA is reduced to 0.40 and  pB=0.40 (See stoichiometric representation) 
  Rate =k[0.40][0.40]2   ............(ii)  (ii) divide by (i) =0.40×0.40×0.400.60×0.80×0.80=16

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